The split manifold is a general term for a diverter valve, a manifold valve, and a split manifold. The function of the diverter valve is to supply the same flow rate (equal shunt) from the same energy source to the two actuators in the hydraulic system to achieve a synchronized or proportional relationship between the speeds of the two actuators. The function of the collecting valve is to collect equal flow or proportional oil return from the two actuators to achieve speed synchronization or proportional relationship therebetween. The split manifold has the functions of a diverter valve and a manifold.
The structural principle of the equal-number diverter valve . Set the inlet oil pressure to p0 and the flow rate to q0. After entering the valve, the two channels are respectively passed through two fixed orifices 1 and 2 of equal area, respectively entering the oil chambers a and b, and then by the variable orifices 3 and 4. The oil outlets I and II lead to two actuators. If the loads of the two actuators are equal, the outlet pressure of the split port is p3 = p4. Since the sizes of the two runners in the valve are completely symmetrical, the output flow is also symmetrical, q1 = q1 = q0/2, and p1 = p2. When p3≠p4 occurs due to load asymmetry, and p3>p4 is set, the spool is not in motion and is in the middle position. Since the total resistance on the two runners is the same, q1p2 must be made. At this time, the spool moves to the left under the action of the asymmetric hydraulic pressure, so that the variable orifice 3 is increased, and the orifice 4 is decreased, so that q1 is increased and q2 is decreased until q1≈q2, p1≈p2. The spool is stabilized in a new equilibrium position. That is, the flow rate to the two actuators is equal, and when the two actuators are exactly the same size, the motion speed will be synchronized.
In the case of the splitting condition, since p0 is larger than p1 and p2, the spools 5 and 6 are in a state of being separated from each other. If the load pressure p3>p4, if the spool remains in the middle position, p2>p1 must be made. This is that the integrated spool will move to the left, the variable orifice 3 will decrease, and p1 will rise until p1≈p2, and the spool will stop moving. Since the areas of the two fixed orifices 1 and 2 are equal, the flow rate q1 ≈ q2 through the two fixed orifices is not affected by changes in the outlet pressures p3 and p4.
In the collecting condition, since p0 is smaller than p1 and p2, the two spools are in a state of being pressed against each other. Set the load pressure p4>p3. If the spool remains in the middle position, p2>p1 must be made. At this time, the compacted valve body is shifted to the left, and the variable orifice is reduced, so that p2 is lowered until p2≈p1, and the spool stops moving. Therefore, q1 ≈ q2, and is not affected by changes in import pressures p3 and p4.
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